**GSEB Solutions for Class 6 Mathematics – Revision: 1 (Sem -II)**

GSEB SolutionsMathsScience

**Revision – 1**

**Solution 1(1):**

3 C. 6

3 -(-3) = 3 + 3 = 6

(Subtracting a negative number is the same as adding its positive integer)

**Solution 1(2):**

B. 1

(-5) + 6 =1

Start from (-5) and move 6 unit places to the right, we get 1; or to add 6 to (-5), subtract 5 from 6 and place the sign of the greater integer, hence positive 1.

**Solution 1(3):**

C. 58°

Measure of the complementary angle of an angle = 90˚ – Measure of the given angle

The measure of given angle = 32˚

∴ Measure of complementary angle of 32˚= 90˚ – 32˚ = 58˚

**Solution 1(4):**

B. 148°

Measure of supplementary angle of an angle = 180˚ – Measure of the given angle

The measure of given angle = 32˚

∴ Measure of complementary angle of 32˚= 180˚ – 32˚ = 148˚

**Solution 1(5):**

A. 55°

The angles forming a linear pair are always supplementary.

∴The sum of measures of angles of a linear pair = 180˚

The measure of given angle = 125˚

∴Measure of angle forming its linear pair = 180˚ – 125˚ = 55˚

**Solution 1(6):**

C. 1

Factors of 13: 1, 13

Factors of 22: 1, 2, 11, 22

The common factor of 13 and 22 is 1

∴ H.C.F of 13 and 22 is 1

**Solution 1(7):**

D. 42

L.C.M of 14 and 42 = 2 × 3 × 7 = 42

**Solution 2:**

**Solution 3:**

**Solution 4:**

Given,

m∠MON = 120°

From the figure, ∠MON and ∠MOJ form a linear pair.

m∠MON + m∠MOJ = 180°

120° + m∠MOJ = 180°

m∠MOJ = 180° – 120° = 60°

m∠MON = m∠JOG = 120° [vertically opposite angles]

m∠MOJ = m∠NOG = 60° [vertically opposite angles]

The measures of the other three angles are 120°, 60° and 60°.

**Solution 5:**

**Solution 6:**

- Two pairs of vertically opposite angles are formed.
- The pairs of vertically opposite angles are: ∠ACX and ∠BCY; ∠ACY and ∠BCX.
- There are four pairs of angles of linear pair are formed.
- The pairs of angles of linear pair are:
- ∠ACY and ∠BCY, ∠BCY and ∠BCX, ∠BCX and ∠ACX, ∠ACX and ∠ACY.

**Solution 7:**

Butterfly (a) will sit on flower (2).

Butterfly (b) will sit on flower (1).

Butterfly (c) will sit on flower (3).

Butterfly (d) will sit on flower (5).

Butterfly (e) will sit on flower (4).

**Solution 8:**